5m^2=108

Solution for 5m^2=108 equation:

5m^2=108

We move all terms to the left:

5m^2-(108)=0

a = 5; b = 0; c = -108;
Δ = b2-4ac
Δ = 02-4·5·(-108)
Δ = 2160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2160}=\sqrt{144*15}=\sqrt{144}*\sqrt{15}=12\sqrt{15}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{15}}{2*5}=\frac{0-12\sqrt{15}}{10}
=-\frac{12\sqrt{15}}{10}
=-\frac{6\sqrt{15}}{5}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{15}}{2*5}=\frac{0+12\sqrt{15}}{10}
=\frac{12\sqrt{15}}{10}
=\frac{6\sqrt{15}}{5}
$